That's EXACTLY what we're talking abut here....
(I think some people came into the conversation late.)
I think many people here are confusing absorption with dropoff due to distance.
Of course, as you get further from the source, the sound level will get lower.
(And the math whereby that occurs will depend on the space the sound is radiated into.)
However, assuming that the absorption of all frequencies by the air was equal....
As we got further away the overall amplitude would be lower..... but it would still remain proportionally equal at all frequencies.
So, if the cymbals were at a certain SPL level at one inch, and 5% of their energy was at 30 kHz......
The level would somewhat lower at two meters, but 5% of the energy at that distance would still be at 30 kHz.....
HOWEVER, the reality is that the absorption of different frequencies by air is NOT at all equal.
The absorption by air at 200 Hz is very close to 0 dB.
The absorption at 30 kHz (under the other conditions I listed) is about 0.9 dB/meter.
So, as the distance increases, you will lose proportionally more amplitude as the frequency goes up.
So, for whatever distance you choose, you calculate the predicted amplitude, based on the distance dropoff calculations.
Then, for relatively high frequencies, you ADD the additional attenuation that occurs because of absorption by the air.
So, for example, at two meters, the level at 200 Hz will be what you would expect based on the "dropoff calculations"...
But, at two meters, the level at 30 kHz will be 3.6 dB lower than that due to the ADDITIONAL loss of 3.6dB due the energy absorbed by the air at that distance and frequency.
@gregorio's original assertion was essentially that:
"Even if there is a significant amount of 30 kHz being produced by the cymbal it won't matter because the air will absorb it all before it reaches the microphone."
He then went on to assert that the loss would be something like 50 dB at 20 meters.
However, those numbers are not correct.
According to the calculations, at two meters, which is what I specified, the energy at 30 kHz will have lost an additional 3.6 dB due to air losses in addition to the dropoff caused by the distance.
In other words, if you measure it, at two meters the cymbals should show an additional roll off of 3.6 dB at 30 kHz compared to the level at relatively low frequencies.
This is quite different than claiming that "nothing at 30 kHz would remain".
(Note that all of the numbers I quoted were for 50% relative humidity and 20 degrees Centigrade at sea level pressure).
We all realize that OVERALL level will drop with distance.
The discussion revolves around how much ADDITIONAL loss there will be at ultrasonic frequencies due to air absorption.
So, for example, if the total attenuation at 2 meters at 200 Hz calculates out to 14 dB, we would expect the drop off at 30 kHz to measure 17.6 dB (which is pretty far from "nothing measurable or recordable remaining").
OK, I get that, makes total sense. But then since we are comparing normal audio to ultrasonics, (the argument being... ultrasonics don't matter because they're too attenuated relative to normal sound to matter) isn't the relative atmospheric absorption the most relevant number?
I mean, yes, certainly, 14db total attenuation at 2m, but unless I'm missing something, that value would be similar at (say) 200hz also.